Respuesta :
Answer:
T_stop = 0.30952 hr = 18.57 mins
Explanation:
Given:
- The distance between two towns S = 340 mi
- Speed of the room-mate v_r = 60 mi/h
- Our Speed v_o = 70 mi / h
- Both drive at their receptive speeds for 1 hr.
- We stop for time t_stop
- We need to arrive 0.5 hrs earlier than our room mate
Find:
how long can you stay at the rest stop before resuming your drive?
Solution:
- Total time taken by room-mate:
T_r = S / v_r
T_r = 340 / 60 = 17/3 hrs
- Total time taken by you:
T_o = T_1hr + T_stop + T_resume
- We are given that we must reach 0.5 hrs earlier than your room-mate:
T_o = T_r - 0.5
- Hence,
T_stop = T_r - 0.5 - T_resume - T_1hr.
- Plug in the values:
T_stop = 17/3 - 0.5 - 1 - ( 340 - v_o*1hr) / v_o
T_stop = 31/6 - 1 - (340 - 70) / 70
T_stop = 25/6 - 27/7
T_stop = 0.30952 hr = 18.57 mins