a) 5 quarts of antifreeze are in resulting mixture
b) percentage of the resulting mixture is antifreeze is 47.2 %
Solution:
Given that,
3 quarts of a solution that is 22% antifreeze is mixed with 2 quarts of a solution that is 85% antifreeze
The total volume of the resulting mixture iS 3 + 2 = 5 quarts
Therefore,
3 quarts of a solution that is 22% antifreeze is mixed with 2 quarts of a solution that is 85% antifreeze to get a resulting mixture of 5 quarts that is x % antifreeze
Thus we get,
[tex]22 \% \times 3 + 85 \% \times 2 = x \% \times 5\\\\\frac{22}{100} \times 3 + \frac{85}{100} \times 2 = \frac{x}{100} \times 5\\\\0.22 \times 3 + 0.85 \times 2 = 0.01x \times 5\\\\0.66 + 1.7 = 0.05x\\\\0.05x = 2.36\\\\x = \frac{2.36}{0.05} = 47.2[/tex]
Thus percentage of the resulting mixture is antifreeze is 47.2 %
