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The permanent electric dipole moment of the water molecule (H2O) is 6.2×10−30C⋅m.The permanent electric dipole moment of the water molecule (H2O) is 6.2×10−30C⋅m. What is the maximum possible torque on a water molecule in a 4.5×10^8 N/C electric field? Express your answer using two significant figures.

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zainsubhani

Answer:

[tex]T=2.8*10^{-21}\ N.m[/tex]

Explanation:

Torque on a molecule in an electric field is given by the cross product of Dipole moment and electric field:

T=PxE=PEsinΘ

where

P is electric dipole moment

E is electric field

Θ is the angle between and E

In case of maximum torque, the angle between P and E is 90 degree.So, Maximum torque=T=P.E

[tex]T=(6.2*10^{-30})*(4.5*10^{8})\\T=2.79*10^{-21}\ N.m[/tex]

Using two significant figures

[tex]T=2.8*10^{-21}\ N.m[/tex]

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