Answer:
(a) [tex]-\sqrt{10}y[/tex]
(b) [tex]-\sqrt{3}y[/tex]
Step-by-step explanation:
(a) [tex]\sqrt{10y^{2}}[/tex] can also be written as [tex]\sqrt{10}[/tex] x [tex]\sqrt{y^{2}}[/tex]
the [tex]\sqrt{y^{2}}[/tex] = ± y
Therefore :
[tex]\sqrt{10y^{2}}[/tex] = ±[tex]\sqrt{10}y[/tex]
since it was given that y < 0 , then the factor will be [tex]-\sqrt{10}y[/tex]
(b) [tex]\sqrt{3y^{2}}[/tex] can also be written as : [tex]\sqrt{3}[/tex] x [tex]\sqrt{y^{2}}[/tex]
Therefore , one of the factor is [tex]-\sqrt{3}y[/tex]
