Respuesta :
Answer:
Explanation:
Given that each of the rain drop sphere has a voltage of V
And their are 8 rain drops that want to coalesce
Electric potential is given as
U=Kq/r
If each has a radius r before coalesce then it volume is 4πr³/3
The volume of all the eight raindrops when they coalesce is 4πR³/3 which is equal to the 8 times each volume
Then,
4πR³/3=8× 4πr³/3
Then π, 4 and 3 cancel out
R³=8r³
Find cube root of both sides
R=2r
So the radius of the big raindrop is 2r
The electric potential of each of the sphere is
U=Kq/r= V
Now, for the eight raindrops the charges inside the big raindrops will be eight multiple each rain drops Q=8q
Therefore, electric potential of the big rain drops (Ub) is
Ub=KQ/R.
Where Q=8q and R=2r
Ub=K•8q/2r
Ub=4kq/r
Ub=4•kq/r. Since U=Kq/r= V
Then, Ub=4V
The answer is D.
When They coalesce to make one spherical raindrop whose potential is 4V. The Correct Option is 'D'.
Calculate Spherical Raindrop
Given that as per the question each of the raindrop spheres has a voltage of V.
And 8 raindrops want to coalesce
After that, Electric potential is given as
Then, U=Kq/r
Now, If each has a radius r before coalesce then its volume is 4πr³/3
When The volume of all the eight raindrops Then, they coalesce is 4πR³/3 which is equal to the 8 times each volume
Then, 4πR³/3=8× 4πr³/3
After that, π, 4, and 3 cancel out
R³=8r³
Now, Find The cube root of both sides
That, R is =2r
So when the radius of the big raindrop is 2r
Then, The electric potential of each the sphere is
U=Kq/r= V
After that, for the eight raindrops, the charges inside the big raindrops will be eight multiple each rain drops Q is =8q
Thus, the electric potential of the big raindrops (Ub) is
So, Ub=KQ/R.
Where Q=8q and R=2r
Now, Ub=K•8q/2r
Ub=4kq/r
Ub=4•kq/r. Since U=Kq/r= V
Then, Ub=4V
Therefore, The Option is D.
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