Answer: The concentration of barium acetate solution is [tex]5.35\times 10^{-4}M[/tex]
Explanation:
To calculate the molarity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}[/tex]
Moles of barium acetate = [tex]107\mu mol=1.07\times 10^{-4}mol[/tex] (Conversion factor: [tex]1mol=10^6\mu mol[/tex] )
Volume of solution = 200 mL
Putting values in above equation, we get:
[tex]\text{Molarity of barium acetate}=\frac{1.07\times 10^{-4}\times 1000}{200}\\\\\text{Molarity of barium acetate}=5.35\times 10^{-4}M[/tex]
Hence, the concentration of barium acetate solution is [tex]5.35\times 10^{-4}M[/tex]
