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Consider an ideal gas enclosed in a 1.00 L container at an internal pressure of 10.0 atm. Calculate the work, w , if the gas expands against a constant external pressure of 1.00 atm to a final volume of 10.0 L.

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jamesesther1234

Answer:

The answer to this question is 1,013 Joules or 1.013 kJ.

Explanation:

This process is an isobaric process as pressure is constant throughout.

Work done by gas expansion, W

= P Δ V   ; (where P = pressure, ΔV = change in volume)

W = 10 atm (10 - 1 ) L

W =  10 L. atm ⇒ 10 × [tex]\frac{101.3 J}{ 1 L.atm}[/tex]

W = 1,013 Joules ≈ 1. 01 kJ.

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