Answer:
[tex]h = 0.0231 m[/tex]
Explanation:
The movement of the coin is modelled after the Principle of Energy Conservation. The kinetic energy of the coin is the sum of the components associated with translation and rotation and there are no non-conservative forces. In addition, the coin starts moving at height of zero
[tex]K_{rot} + K_{tr} = U_{g}[/tex]
[tex]\frac{1}{2} \cdot m_{coin} \cdot \omega^{2} \cdot R^{2} + \frac{1}{4} \cdot m_{coin} \cdot R^{2} \cdot \omega^{2} = m_{coin} \cdot g \cdot h\\[/tex]
[tex]\frac{3}{4} \cdot R^{2} \cdot \omega^{2} = g \cdot h[/tex]
The maximum vertical height is isolated in the previous equation:
[tex]h = \frac{3 \cdot R^{2}\cdot \omega^{2}}{4\cdot g}[/tex]
[tex]h = \frac{3 \cdot (0.01115 m)^{2} \cdot (49.3 \frac{rad}{s} )^{2}}{4 \cdot (9.807 \frac{m}{s^{2}} )} \\h = 0.0231 m[/tex]
