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The length and mass of the arm are Larm = X1 = 50 cm and Marm = 0.3 kg, X2 = 15 cm, and the mass of the object is MObject = 0.25 kg. For this problem you may assume that the hook at the end of the arm is massless and the gravitational constant can be approximated as g = 10 m/s2 Develop a symbolic expression for the torque required by the motor to lift the object off of the sand.

Respuesta :

Answer: 0.5N

Explanation: if the system is at equilibrium, sum of the torque will be equal to zero.

But if they are not in equilibrium.

U will find the difference in the two torque

find the attached file for solution

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