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An aqueous solution containing 4.95 g of an optically pure compound was diluted to 700.0 mL with water and placed in a polarimeter tube 15.0 cm long. The measured rotation was –3.65° at 25 °C. Calculate the specific rotation of the compound.

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Answer:

[∝] = 344.1°

Explanation:

The formula of specific rotation is:

[∝] = ∝ / c×l

Where [∝] is specific rotation, ∝ is measured rotation, c is concentration is g/mL and l is path length in decameters

Concentration is:

4.95g/700.0mL = 7.071x10⁻³ g/mL

Path length is:

15.0cm ₓ (1dm / 10cm = 1.50dm

Replacing:

[∝] = -3.65° / 7.071x10⁻³ g/mL×1.50dm

[∝] = 344.1°

I hope it helps!

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