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A 129 turn circular coil of radius 2.85 cm is immersed in a uniform magnetic field that is perpendicular to the plane of the coil. Over an interval of 0.153 s , the magnetic field strength increases from 53.7 mT to 93.3 mT . Find the magnitude of the average emf E avg induced in the coil during this time interval, in millivolts.

Respuesta :

Answer:

85.24 mV

Explanation:

From Faraday's law of induction,

Emf induced = - NA (dB/dt)

Average emf induced = NA (ΔB/Δt)

N = number of turns = 129

A = Area of the loop = πr² = π(0.0285)² = 0.002553 m²

ΔB = 93.3 - 53.7 = 39.6 mT = 0.0396 T

Δt = 0.153 s

E = (129)(0.002553)(0.0396)/(0.153)

E = 0.08524 V = 85.24 mV

akande212

Answer:

E = -84.3mV

Explanation:

The average induced emf is a function of the number of turns of the coil, the change in magnetic flux per unit time. Mathematically it is represented as

E =-NdФ/dt

We have been given the radius from which we can calculate the area. The area is πr². With the area we can calculate the change in the magnetic flux per time having known B at different times.

Ver imagen akande212