Answer:
z-score = -0.25
[tex]P(x \leq 475) =0.401[/tex]
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 500
Standard Deviation, σ = 100
Formula:
[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]
We have to evaluare
:[tex]P( x \leq 475) = P( z \leq \displaystyle\frac{475 - 500}{100}) = P(z\leq -0.25)[/tex]
Calculation the value from standard normal z table, we have,
[tex]P(x \leq 475) =0.401 =40.1\%[/tex]