Answer:
V = (-32t +32) ft/s
The velocity of the bowling ball after t seconds is the time derivative of the position function s(t). To obtain the velocity from s(t) we simply differentiate s(t) with respect to t. That is
V = ds(t)/dt = -16×2t + 32×1 = -32t + 32.
When differentiating, you multiply the coefficient of each term in the equation with the power of the variable and then reduce the power by 1 just like above.
Explanation:
