pr4e4ttienthiomeS
pr4e4ttienthiomeS pr4e4ttienthiomeS
  • 06-07-2016
  • Chemistry
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calculate the mass of butane needed to produce 46.4 g of carbon dioxide

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Willchemistry
Willchemistry Willchemistry
  • 06-07-2016
Molar mass:

CH₄ = 12 + 1 x 4 = 16.0 g/mol

CO₂ = 12 + 16 x 2 = 44.0 g/mol

Balanced equation :

CH₄ + 2 O₂ = CO₂ + 2 H₂O

16.0 g CH₄ --------------- 44.0 g CO₂
(mass of CH₄) ----------- 46.4 g CO₂

mass of CH₄ = 46.4 x 16.0 / 44.0

mass of CH₄ = 742.4 / 44.0

= 16.87 g CH₄

hope this helps!
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