Answer:
1.2 m/s
Explanation:
The puck in this problem is moving with uniform circular motion, so the net force acting on it (the tension in the string) must be equal to the centripetal force.
So we can write:
[tex]T=m\frac{v^2}{r}[/tex]
where:
T is the tension in the string
m is the mass of the puck
v is its tangential speed
r is the radius of the circular path
For the puck in this problem, we have:
m = 0.5 kg
T = 1.0 N
r = 0.7 m
Substituting and solving for v, we find the tangential speed:
[tex]v=\sqrt{\frac{Tr}{m}}=\sqrt{\frac{(1.0)(0.7)}{0.5}}=1.2 m/s[/tex]
