Answer:
Therefore,
The resistor value , R is 9.4 kΩ.
Explanation:
Given:
A neon gas tube has
Von = 60.0 V and
Voff = 30.0 V
Capacitor, C = 20.0 μF
Battery , E = 120 V
Frequency = f = 30 hz
[tex]Time\ period =T=\dfrac{1}{f}=\dfrac{1}{30}=0.033\ s[/tex]
To Find:
Resistor , R =?
Solution:
Time period of the wave will be only the charging time of the capacitor,the capacitor will be charged to Von from initial voltage Voff is given by,
[tex]T=RC\ln(\dfrac{E-V_{off}}{E-V_{on}})[/tex]
Where,
R = Resistance
C =Capacitance
E = Battery in volts
ln = natural Log (Sign)
Substituting the values we get
[tex]0.033=R\times 20\times 10^{-6}\ln(\dfrac{120-30}{120-60})[/tex]
[tex]0.033=R\times 20\times 10^{-6}\ln(1.5)[/tex]
[tex]0.033=R\times 20\times 10^{-6}\times 0.176[/tex]
[tex]R=9.375\times 10^{3}=9.4\ k\Omega[/tex]
Therefore,
The resistor value , R is 9.4 kΩ.
