Answer:
v = 2 x 10⁶ m/s
Explanation:
Given,
Magnetic field, B = 0.22 T
E = 0.44 MV/m
Speed of the particle = ?
We know,
F = q v B
And also
Relation between Force and electric field
F = q E
q v B = q E
[tex]v = \dfrac{E}{B}[/tex]
[tex]v = \dfrac{0.44\times 10^6}{0.22}[/tex]
v = 2 x 10⁶ m/s
The Speed of the particle is equal to v = 2 x 10⁶ m/s
