Answer:
The mass of the sample used for the titration is 0.025 g
Explanation:
Given;
mass of the sample = 0.075 g
volume of aqueous solution = 30 mL
volume of solution used in the titration = 10 mL
[tex]Concentration \ of \ the \ sample(\frac{g}{mL}) = \frac{mass(g)}{volume(mL)} = \frac{0.075g}{30mL} =2.5*10^{-3} \frac{g}{mL}[/tex]
If the volume of the solution used in titration is 10 mL, the mass of the sample used for the titration is;
M = CV;
Where;
m is the mass of the sample;
c is the concentration of the solution
v is the volume of the solution used
m = 2.5 x 10⁻³ x 10 = 2.5 x 10⁻² g = 0.025 g
Therefore, the mass of the sample used for the titration is 0.025 g
