Respuesta :

dalendrk
[tex](x^2)\left(2xy^3\right)^5=(x^2)\left(2^5x^5y^{3\cdot5}\right)=(x^2)(32x^5y^{15})\\\\=32x^{2+5}y^{15}=\boxed{32x^7y^{15}}\to\boxed{c.}[/tex]

Answer:

c

Step-by-step explanation:

We can solve and simply the expression using the product rule for the following expression:

[tex]=x^2*(2*x*y^5)^5[/tex]

If x is multiplied by a x we can add their exponents, if a bracket has an exponent we can multiply the exponent with the exponent of each term in the bracket.

[tex]=x^2*(2^5*x^5*y^15)[/tex]

[tex]=32*x^7*y^15[/tex]

Therefore the answer is c