Answer:
Electric field due to two charges is given as
[tex]E = 1.44 \times 10^7 N/C[/tex]
Explanation:
As we know that two charges are opposite in nature
So the electric field at the mid point of two charges will add together
so the net field is given as
[tex]E = 2\frac{kq}{r^2}[/tex]
now we have
[tex]q = 2\times 10^{-6} C[/tex]
[tex]r = 5 cm = 0.05 m[/tex]
now we have
[tex]E = 2\frac{(9\times 10^9)(2\times 10^{-6})}{0.05^2}[/tex]
[tex]E = 1.44 \times 10^7 N/C[/tex]
