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The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 40.8° what is the index of refraction of the material?

Respuesta :

Olajidey

Answer:

the index of refraction of the material is 1.53

Explanation:

c=40.8 degree

c = sin⁻¹ (n2/n1)

n2=1

then

For total internal reflection

sin40.8 = 1 / n1

0.6534 = 1 / n1

n1 = 1 / 0.6534

n1 = 1.53

Thus, the index of refraction of the material is 1.53