Answer:
The value of Kp for the system = 0.0128 atm
Explanation:
Let, the gaseous substance is SO₂Cl₂
SO₂Cl₂ ⇄ SO₂ + Cl₂
Initially x 0 0
At equilibrium (x - 14.5%x) 14.5%x 14.5%x
= 85.5 % x
Total moles of gases at equilibrium
= 85.5 % x + 14.5%x + 14.5%x
= 114.5 % x
Partial pressure of SO₂ ([tex]Pso_{2}[/tex]) = [tex]\frac{14.5x}{114.5x} X0.67= 0.08[/tex]
Partial pressure of Cl₂ [tex](Pcl_{2}) =\frac{14.5x}{114.5x} X0.67 = 0.08[/tex]
Partial pressure of SO₂Cl₂ [tex](Pso_{2}cl_{2} )=\frac{85.5x}{114.5x} X0.67= 0.5[/tex]
So,
[tex]Kp = \frac{Pso_{2} XPcl_{2} }{Pso_{2}cl_{2}}\\ \\=\frac{0.08X0.08}{0.5} \\\\=0.0128[/tex]
