Answer:
The maximum contact pressure is 12.658 ksi
Explanation:
The contact modulus is:
Δ = M
[tex]M=2*(\frac{1-v^{2} }{E} )=2*(\frac{1-0.3^{2} }{30x10^{6} } )=6.06x10^{-8} in^{2} /lb[/tex]
The radius of curvature is:
r1 = D1/2 = 1.4/2 = 0.7 in
r2 = D2/2 = 3.4/2 = 1.7 in
The maximum contact pressure is:
[tex]P=0.564\sqrt{\frac{F*(\frac{1}{r_{1} }+\frac{1}{r_{2} }) }{L*M} } =0.564\sqrt{\frac{56*(\frac{1}{0.7}+\frac{1}{1.7}) }{3.7*6.06x10^{-8} } } =12658.09psi=12.658ksi[/tex]
