U = 80mph = 35.76m/s
S = 0.8m
M = 3500kg
To find the deceleration, we use equation of motion to calculate that
V² = u² + 2as
But v = 0
0 = u² + 2as
-U² = 2as
a = -u² / 2s
a = -(35.76)² / (2 * 0.8)
a = 1278.78 / 1.6 = 799.24 m/s²
The force exerted on the truck during deceleration is equal to the summation of all the forces acting on the truck.
∑F = m. ⃗a
-F = 3500 * 799.24
F = -2797331.25N
F = -2797.33kN
F = -2.797MN.
