Don put $4,000 in a savings account with an interest rate of 4% for three years. If the interest is compounded annually, how much money will he have at the end of the three years?

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qop

Answer:

$4,499.46

Step-by-step explanation:

We can use the compound interest formula for this problem:

[tex]A=P(1+\frac{r}{n} )^{nt}[/tex]

P = initial balance

r = interest rate (decimal)

n = number of times compounded annually

t = time

First, lets change 4% into a decimal:

4% -> [tex]\frac{4}{100}[/tex] -> 0.04

Now lets plug the values into the equation as shown below:

[tex]A=4,000(1+\frac{0.04}{1})^{1(3)}[/tex]

[tex]A=4,499.46[/tex]

Don will have $4,499.46 at the end of the three years.