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An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.10 mm. (a) If a 24.0 V potential difference is applied to these plates, calculate the electric field between the plates.

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asuwafohjames

Answer:

11428.57 N/C.

Explanation:

Electric Field: This an be defined as the the force per unit charge which is exerted at that point. The S.I unit of electric Field is N/C or V/m

From the question,

E = V/d................ Equation 1

Where E = Electric Field, V = potential difference applied to the end of these plates, d = distance of separation between the plates.

Given: V = 24 V, d = 2.10 mm = 2.1/1000 = 0.0021 m

Substitute into equation 1

E = 24/0.0021

E = 11428.57 N/C.