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A 150 kg uniform beam is attached to a vertical wall at one end and is supported by a cable at the other end. a) Calculate the magnitude of the vertical component of the force that the wall exerts on the left end of the beam if the angle between the cable and horizontal is θ = 47°.

Respuesta :

Answer:

1004.277N

Explanation:

Given that g = 9.817 ms^-2

If the angle between the cable and horizontal is 47°.

The angle between the cable and vertical is 90-47= 43°.

The weight of the beam is mg

The weight of the beam is

= 150*9.817

The weight of the beam is

= 1472.55N

magnitude of the vertical component of the force is mgsin(tita)

= 1472.55*sin43

= 1004.277N

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