Answer:
The quantity of sludge solids is 107.69 pounds approximated to 108 pounds.
Step-by-step explanation:
Given:
Quantity of the volatile matter in the dig-ester = 1400 pounds
Volatile solids added per day per pound = 0.05
According to the question :
The added sludge solid in the dig-ester have 65% of volatile content.
Lets say that the total sludge added be 'x' pound.
⇒ The volatile content = [tex]65\%[/tex]
⇒ And sludge added = [tex]0.05\times 1400[/tex]
= [tex]70[/tex] pounds
So,
⇒ The total quantity of sludge added:
⇒ [tex]65\% \ of \ x=70[/tex]
⇒ [tex]\frac{65}{100}\times x = 70[/tex]
⇒ [tex]65x=70\times 100[/tex]
⇒ [tex]x=\frac{70\times 100}{65}[/tex]
⇒ [tex]x=\frac{7,000}{65}[/tex]
⇒ [tex]x=107.69[/tex] pounds
The quantity of sludge solids that an be added per day with a volatile content of 65% is 107.69 approximated to 108 pounds.
