Answer:
Mass of SO₂ can be made from 25.0 g of Na₂SO₃ and 22 g of HCl = 12.672 g
Explanation:
SO₂( sulfur dioxide) can be produced in the lab. by the reaction of hydrochloric acid & sulphite salt such as sodium.
the balanced chemical equation is as follows
Na₂SO₃ + 2 HCl → 2 NaCl + SO₂ + H₂O
Moles of Na₂SO₃ = [tex]\frac{Mass}{Molecular mass} =\frac{25}{126} = 0.198[/tex]
Moles of HCl = [tex]\frac{mass}{molecular mass}=\frac{22}{36.5}= 0.6[/tex]
using mole ratio method to find limiting reagent
For sodium sulfite [tex]\frac{mole}{stoichiometry} = \frac{0.198}{1}= 0.198[/tex]
for HCl [tex]\frac{mole}{stoichiometry} = \frac{0.6}{2}= 0.3[/tex]
since sodium sulfite is limiting reactant for above chemical reaction
1 mole of Na₂SO₃ produce 1 mole of SO₂
0.198 mole of Na₂SO₃ produce 0.198 mole of SO₂
∴ Mass of SO₂ produce = mole x molar mass of SO₂
= 0.198 x 64
= 12.672 g
