Answer:
P(at least 3) = 0.35
Step-by-step explanation:
We are given the following probability distribution in the question:
x: 0 1 2 3 4 5
P(x): 0.10 0.25 0.30 0.20 0.10 0.05
where x is the number of customers in line at a supermarket
Verification for a discrete probability distribution:
[tex]\displaystyle\sum P(x_i) = 1\\\\\displaystyle\sum P(x_i) = 0.10 +0.25 +0.30 +0.20 +0.10 +0.05 = 1[/tex]
Hence, it is a discrete probability distribution.
We have to evaluate P(at least 3).
[tex]P(x\geq 3)\\=1 - P(x<3)\\=1- (P(x=0) + P(x=1) + P(x=2))\\=1 - (0.10 +0.25 +0.30)\\=0.35[/tex]
Thus,
P(at least 3) = 0.35
0.35 is the probability that there are atleast 3 customers in line at a supermarket.
