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Stock solutions of nitric acid have concentration of 16.0 M. What volume of stock solution is needed to prepare 2.00 L of 2.00 M solution of nitric acid by dilution with water?
500 mL
125 mL
250 mL
32.0 mL
62.5 mL

Respuesta :

mberisso

Answer:

250 mL

Explanation:

These are the variable one has to have in mind:

[tex]C_1[/tex] = 16 M

[tex]C_{2}[/tex] = 2 M

[tex]V_{2}[/tex] = 2 L = 2000 mL

Note: C = concentration; V = volume; subscript 1 = stock solution; subscript = 2 = dilution.

What we have to solve is for [tex]V_{1}[/tex]

Use the following equation:

[tex]C_{1}[/tex] x [tex]V_{1}[/tex] = [tex]C_{2}[/tex] x [tex]V_{2}[/tex] ⇒ [tex]V_{1}[/tex] = [tex]\frac{2M x 2000 mL}{16M}[/tex] ⇒  [tex]V_{1}[/tex] = 250 mL