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Part B
Open the graphing tool, and compare the functions using the sliders. What can be said about the domain of
y = sqare root if x - k and the domain of y = square root of x + k?

Part B Open the graphing tool and compare the functions using the sliders What can be said about the domain of y sqare root if x k and the domain of y square ro class=

Respuesta :

Answer:

In y=[tex]\sqrt{x-k}[/tex] , the domain depends on k . As you slide k , you move the left bound of the domain interval. In y=[tex]\sqrt{x+k}[/tex]  , the domain is fixed and always starts at 0 .

Step-by-step explanation: