A submersible vessel was
lowered 6 meters from its start
position and raised 50 meters.
The vessel then lowered itself 5.5
meters each hour for 7 hours.
How many meters is the vessel
from its start position?

Respuesta :

Answer:

5.5 meters above start position.

Step-by-step explanation:

-Let X be the start position.

#Total distance below the start position is calculated as:

[tex]d_{down}=6+5.5\times 7\\\\=44.5\ m[/tex]

#Total distance above the start position X:

[tex]d_{up}=50\ m[/tex]

#Distance above/below start position is:

[tex]d=X-d_{down}+d_{up}\\\\=X-44.5+50\\\\d=X+5.5\ m[/tex]

Hence, The vessel is 5.5 meters above the start position