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A standard soft drink can has a volume of 0.355 L. An empty can is sealed while
holding air at 1.0 atm of pressure. When the can is crushed to 0.125 L, what is the
pressure inside the can?

Respuesta :

PunIntended

Answer:

0.35 atm

Explanation:

To solve this problem, we use Boyle's Law: [tex]P_1V_1=P_2V_2[/tex] , where P is the pressure and V is the volume.

Here, V_1 = 0.355 L, P_1 = 1.0 atm, and V_2 = 0.125 L. So, just plug these values into the equation:

(1.0) * (0.355) = [tex]P_2[/tex] * (0.125)  ⇒  [tex]P_2[/tex] ≈ 0.35 atm

Thus, the pressure is 0.35 atm.

Hope this helps!

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