Respuesta :
Answer:
(a) 0.0041 weber
(b) 0.41 volt
Explanation:
diameter of coil, d = 20 cm
radius of coil, r = half of diameter = 10 cm = 0.1 m
magnetic field strength, B = 0.13 tesla
(a)
The angle between the normal of the coil and the magnetic field is 0°.
Magnetic flux, Ф = B x A x Cos 0°
Ф = 0.13 x 3.14 x 0.1 x 0.1 x 1
Ф = 0.0041 Weber
(b)
angle between the magnetic field and the normal of the coil is 90°.
time, t = 10 ms = 0.01 s
final flux = B x A x cos 90° = 0
induced emf = rate of change of magnetic flux
e = (0.0041 - 0) / 0.01
e = 0.41 Volt
Answer:
a) [tex]\phi=0.4084\ T.m^2[/tex]
b) [tex]emf=653.44\ V[/tex]
Explanation:
Given:
diameter of the coil, [tex]d=20\ cm=0.2\ m[/tex]
no. of turns in the coil, [tex]N=16[/tex]
magnetic field strength to which the coil is subjected, [tex]B=0.13\ T[/tex]
time taken by the coil to rotate from normal the field to parallel, [tex]t=10\times 10^{-3}\ s[/tex]
a)
The flux through the coil can be given as:
[tex]\phi=BA[/tex]
where:
[tex]A=[/tex] area enclosed by the section of the coil
[tex]\phi=0.13\times \pi\times \frac{0.2^2}{4}[/tex]
[tex]\phi=0.4084\ T.m^2[/tex]
b)
When the coil is rotated there is change in flux which lead to an induced emf in the coil according to the Faraday's law:
[tex]emf=N\frac{d\phi}{t}[/tex]
where:
[tex]d\phi=[/tex] change in the flux
here the flux changes from maximum value to zero when the coil becomes parallel to the field lines because then there is no field line intercepting the coil area.
[tex]emf=16\times \frac{0.4084}{0.01}[/tex]
[tex]emf=653.44\ V[/tex]
