Respuesta :
Answer:
0.9826 = 98.26% probability that the sample proportion will differ from the population proportion by less than 0.03.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
For a proportion p in a sample of size n, we have that [tex]\mu = p, \sigma = \sqrt{\frac{p(1-p)}{n}}[/tex]
In this problem, we have that:
[tex]p = 0.07, n = 411[/tex]
So
[tex]\mu = 0.07[/tex]
[tex]\sigma = \sqrt{\frac{0.07*0.93}{411}} = 0.0126[/tex]
If 411 are sampled, what is the probability that the sample proportion will differ from the population proportion by less than 0.03?
This is the pvalue of Z when X = 0.07+0.03 = 0.1 subtracted by the pvalue of Z when X = 0.07 - 0.03 = 0.04. So
X = 0.1
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{0.1 - 0.07}{0.0126}[/tex]
[tex]Z = 2.38[/tex]
[tex]Z = 2.38[/tex] has a pvalue of 0.9913
X = 0.04
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{0.04 - 0.07}{0.0126}[/tex]
[tex]Z = -2.38[/tex]
[tex]Z = -2.38[/tex] has a pvalue of 0.0087
0.9913 - 0.0087 = 0.9826
0.9826 = 98.26% probability that the sample proportion will differ from the population proportion by less than 0.03.
The probability that the sample proportion will differ from the population proportion by less than 0.03 is 0.9826
How to determine the probability
The given parameters are:
[tex]p = 0.07[/tex] -- the true proportion and the mean
[tex]n = 411[/tex] --- the sample size
Start by calculating the standard deviation using
[tex]\sigma = \sqrt{\frac{p(1 - p)}{n}}[/tex]
This gives
[tex]\sigma = \sqrt{\frac{0.07 * (1 - 0.07)}{411}}[/tex]
[tex]\sigma = 0.0126[/tex]
Next, we calculate the x values
[tex]x = x_1 \pm x_2[/tex]
This gives
[tex]x = 0.07 + 0.03,0.07 - 0.03[/tex]
[tex]x = 0.1,0.04[/tex]
Calculate the z score for both x values
[tex]z = \frac{x - \mu}{\sigma}[/tex]
This gives
[tex]z = \frac{0.1 - 0.07}{0.0126},\frac{0.04 - 0.07}{0.0126}[/tex]
[tex]z =2.38,-2.38[/tex]
The p values at the z scores are:
[tex]p = 0.9913,0.0087[/tex]
Calculate the difference
[tex]p = 0.9913-0.0087[/tex]
[tex]p = 0.9826[/tex]
Hence, the probability that the sample proportion will differ from the population proportion by less than 0.03 is 0.9826
Read more about probabilities at:
https://brainly.com/question/25870256
