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Assume that endogenous acid production is 40 meq during a 12-hr period. A urine sample collected during this time contains 30 mmol NH4 and 15 meq titratable acid. If the body is in steady state for HCO3-, how much HCO3- must be in this urine sample?

Respuesta :

Answer:

Thus, the Quantity of [tex]HCo_{3}^{-}[/tex] Present in urine sample in 24 hours is 35mmol

Explanation:

Acid Production in 12 hours = 40 meq

For, 24 hours = 40 meq × 2

Acid Production in 24 hours = 80 meq

Urine sample for [tex]NH4^{+}[/tex] = 30mmol

[tex]HCo_{3}^{-}[/tex] Present in Urine Sample in 24 hours

= Acid Production - Urine sample for [tex]NH4^{+}[/tex] - Titratable Acid

= 80 - 30 - 15

= 50 - 15

= 35mmol

[tex]HCo_{3}^{-}[/tex] Present in urine sample in 24 hours is 35mmol

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