Answer:
The speed of the bob when it passes the lowest point [tex]V = 1.57 \frac{m}{s}[/tex]
Explanation:
Given data
[tex]H = 12.5 \ cm = 0.125 \ m\\[/tex]
When a pendulum swinging back & forth then at highest point the velocity is zero and lowest point velocity is maximum.
Velocity at lowest point is given by
[tex]V = \sqrt{2 g H}[/tex]
[tex]V = \sqrt{2 (9.81)(0.125)}[/tex]
[tex]V = 1.57 \frac{m}{s}[/tex]
Therefore the speed of the bob when it passes the lowest point [tex]V = 1.57 \frac{m}{s}[/tex]
