Option C (-1,2) and (-5,-2) after we solve both the equation.
How to solve a quadratic equation?
A quadratic equation is of the form ax²+bx+c = 0 so to find the solution of the equation we can use the quadratic formula which gives both the roots and is (-b±√(b²-4ac))/2a.
How to find an Intersection Point?
To find the intersection point either we can make the graph of both the equation and then look at the point where both intersect but this method is pretty tedious and needs accuracy so, we equate the same coordinate as at the intersection point their coordinates will remain the same.
The solution to the question
Equating both the equation with y coordinate so,
x+3= x²+7x+8
x²+6x+5=0
x²+5x+x+5=0
x(x+5)+(x+5)
(x+5)(x+1)
Solving the quadratic equation by the given formula we get x= -1 and -5
and according to these values, we put it in y=x+3 and we get y= 2 and -2
so the intersection point is (-1,2) and (-5,2) which means option C is correct.
For more information about intersections refer to https://brainly.com/question/25724532
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