If the side length of the base of a square pyramid is divided by 4 and the slant height is divided by 3, what is the surface area formula that represents these changes?
A. SA = n(1/8lb) + 1/16B
B. SA = n(1/24lb) + 1/16B
C. SA = n(1/24lb) + 1/4B
D. SA = n(1/12lb) + 1/4B
Base area: B = b² B 1 = (b/4)² = b²/16 = B/16 Lateral area: LA = 4 lb /2 LA 1 = 4 l /3 b /8 = 4 · lb/24, n = 4 SA = LA 1 + B 1 Answer: B )SA = n( 1/24 lb ) + 1/16 B
