The power of the truck is "2200 W".
Given:
Force,
Distance,
Time,
As we know,
→ [tex]Power (P) = \frac{FD}{t}[/tex]
By substituting the values, we get
→ [tex]= \frac{11000\times 5}{25}[/tex]
→ [tex]= \frac{55000}{25}[/tex]
→ [tex]=2200 \ W[/tex]
Thus the above approach is appropriate.
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