Answer: 6
Step-by-step explanation:
[tex]-\frac{2}{3}x+9=\frac{4}{3}x-3[/tex]
Subtract [tex]\frac{4}{3}x[/tex] from both sides to leave variables on the left.
[tex]-\frac{4}{3}x-\frac{2}{3}x+9=\frac{4}{3}x-3-\frac{4}{3}x[/tex]
[tex]-\frac{4}{3}x-\frac{2}{3}x+9=-3[/tex]
Now subtract 9 from both sides to isolate independent variables on the right.
[tex]-\frac{4}{3}x-\frac{2}{3}x+9-9=-3-9[/tex]
[tex]-\frac{4}{3}x-\frac{2}{3}x=-3-9[/tex]
Combine like terms;
[tex]-\frac{6}{3}x=-12[/tex]
Simplify;
[tex]-2x=-12[/tex]
To completely isolate x, divide by -2
[tex]\frac{-2x}{-2}=\frac{-12}{-2}[/tex]
[tex]x=6[/tex]
