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If the mass of Mars is 0.11 ME (mass of Earth) and its radius is 0.53 RE (radius of
Earth), How much is the gravitational field g at the surface of Mars?
Given: ME=6.0x1024 kg and RE=6.4x106m

Respuesta :

MathPhys

Answer:

3.8 m/s²

Explanation:

g = GM / R²

g = G (0.11 ME) / (0.53 RE)²

g = 0.39 G ME / RE²

g = 0.39 (9.8 m/s²)

g = 3.8 m/s²

victoria4skye

Answer:

vote me brainliest! Please!

simple put is 3.8 m/s²

took it on edge 2020

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