Answer:
0.181
Explanation:
We can convert the 0.5 rps into standard angular velocity unit rad/s knowing that each revolution is 2π:
ω = 0.5 rps = 0.5*2π = 3.14 rad/s
From here we can calculate the centripetal acceleration
[tex]a_c = \omega^2r = 3.14^2*5.5 = 54.3 m/s^2[/tex]
Using Newton 2nd law we can calculate the centripetal force that pressing on the rider, as well as the reactive normal force:
[tex]F = N = a_cm = 54.3 m[/tex]
Also the friction force and friction acceleration
[tex]F_f = N\mu = 54.3 m \mu N[/tex]
[tex]a_f = F_f / m = 54.3 \mu[/tex]
For the rider to not slide down, friction acceleration must win over gravitational acceleration g = 9.81 m/s2:
[tex]g = a_f = 54.3 \mu[/tex]
[tex]9.81 = 54.3 \mu[/tex]
[tex]\mu = 9.81 / 54.3 = 0.181[/tex]
