The rate of cooling of a cup of tea is required.
The rate of cooling is [tex]\dfrac{1}{20}=0.05\ \text{degree per minute}[/tex]
The given cup of tea cools down [tex]\dfrac{1}{2}[/tex] degree
in [tex]10\ \text{minutes}[/tex]
The rate of cooling will be in the unit of degree per minute.
So,
[tex]10\ \text{minute}=\dfrac{1}{2}\ \text{degree}[/tex]
[tex]1\ \text{minute}=\dfrac{\dfrac{1}{2}}{10}=\dfrac{1}{20}\ \text{degree}[/tex]
The rate of cooling is [tex]\dfrac{1}{20}=0.05\ \text{degree per minute}[/tex]
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