contestada

Consider a simple pendulum with a period
of 5.8 s.
What is its length? The acceleration of
gravity is 9.8 m/s2
Answer in units of m.
part 2 of 2
What would be its period on the Moon,
where its gravity is 1.67 m/s2?
Answer in units of s.
Please help timed will mark brainliess

Consider a simple pendulum with a period of 58 s What is its length The acceleration of gravity is 98 ms2 Answer in units of m part 2 of 2 What would be its per class=

Respuesta :

Answer:

1. The length is 8.35m

2. The period on the moon is 14.05 secs

Explanation:

1. Data obtained from the question. This includes the following:

Period (T) = 5.8 secs

Acceleration due to gravity (g) = 9.8 m/s2

Length (L) =...?

The length can be obtained by using the formula given below:

T = 2π√(L/g)

5.8 = 2π√(L/9.8)

Take the square of both side

(5.8)^2 = 4π^2 x L/ 9.8

Cross multiply

4π^2 x L = (5.8)^2 x 9.8

Divide both side by 4π^2

L = (5.8)^2 x 9.8 / 4π^2

L= 8.35 m

2. Data obtained from the question. This includes the following:

Acceleration due to gravity (g) = 1.67 m/s2

Length (L) = 8.35m (the length remains the same)

Period (T) =?

The period can be obtained as follow:

T = 2π√(L/g)

T = 2π√(8.35/1.67)

T = 14.05 secs

Therefore, the period on the moon is 14.05 secs