Answer:
375g of a carbon-14 isotope
Explanation:
From
N/No = (1/2) t/t1/2
N= mass of isotope remaining after time (t)
No= mass of isotope present at the beginning
t= time taken for mass of isotope to decrease to N
t1/2= half life of the isotope.
Since 1 half-life= 5730 years= t1/2
Four half lives= 4(5730) years= t
No= 6000g of isotope
Then we substitute into the formula
N/6000 = (1/2)^4(5730)/5730
N/6000 = (1/2)^4
N= (1/2)^4 ×6000
N= 375g of a carbon-14 isotope
