A rectangle has a length 6 m less than twice its width. When 3 m are added to the width, the resulting figure is a square with an area of 144 m2. Find the dimensions
of the original rectangle.

Respuesta :

Answer:

Original width = 9m and original length = 12m

Step-by-step explanation:

Let original width be [tex]w[/tex] and original length be [tex]l[/tex].

According to question statement:

[tex]l = 2 \times w -6 ...... (1)[/tex]

When 3m added to width, the resulting figure becomes square with area 144[tex]m^{2}[/tex], also area of a square = [tex]side^{2}[/tex]

[tex]\Rightarrow (w+3)^{2} = 144\\\Rightarrow (w+3) = 12\\\Rightarrow w = 9m[/tex]

Putting value of [tex]w[/tex] in equation (1):

[tex]\Rightarrow l = 2 \times 9 - 6\\\Rightarrow l = 12m[/tex]

Hence, original dimensions of rectangle are:

Length = 12m

Width = 9m