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The rectangle shown has a perimeter of 58 cm and the given area. Its
length is 4 more than four times its width. Write and solve a system of
equations to find the dimensions of the rectangle.

The length of the rectangle is_cm and the width of the rectangle is _cm.

Respuesta :

Chelboy

Answer:width=5cm length=24cm

Step-by-step explanation:

Width=w

Length=L

Perimeter =58

Perimeter=2L+2w

2L+2w=58

There length is 4 more than 4 times it width

L-4=4w

L=4w+4

Substitute L=4w+4 in 2L+2w=58

2(4w+4)+2w=58

8w+8+2w=58

Collect like terms

8w+2w=58-8

10w=50

Divide both sides by 10

10w/10=50/10

w=5 width is 5cm

Substitute w=5 in 2L+2w=58

2L+2(5)=58

2L+10=58

2L=58-10

2L=48

Divide both sides by 2

2L/2=48/2

L=24 length=24cm

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