Respuesta :
Answer:
The final pressure of the gas is 370. kPa
Explanation:
Let's assume the gas inside cylinder behaves ideally.
As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-
[tex]\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}[/tex]
where [tex]P_{1}[/tex] and [tex]P_{2}[/tex] are initial and final pressure respectively.
[tex]V_{1}[/tex] and [tex]V_{2}[/tex] are initial and final volume respectively.
[tex]T_{1}[/tex] and [tex]T_{2}[/tex] are initial and final temperature in kelvin scale respectively.
Another assumption is necessary to solve this problem which is the process should be isothermal.
So [tex]T_{1}=T_{2}[/tex] , [tex]V_{1}=10.0L[/tex] , [tex]P_{1}=163kPa[/tex] and [tex]V_{2}=4.40L[/tex]
Hence [tex]P_{2}=\frac{P_{1}V_{1}}{V_{2}}[/tex]
[tex]\Rightarrow P_{2}=\frac{(163kPa)\times (10.0L)}{4.40L}[/tex]
[tex]\Rightarrow P_{2}=370.kPa[/tex]
So the final pressure of the gas is 370. kPa
